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Need Help with tin weight (Read 5398 times)

Oldman1950 Full Member Offline Posts: 238 Location: Virginia Joined: Feb 8^th, 2014	Need Help with tin weight Sep 1^st, 2020 at 5:53pm	Print Post
	I have 14 lbs. of 1:25 and wish to add tin to make it 1:20 How much tin do I add? Anyone good with the numbers?? Thanks A. J. Palik
	« Last Edit: Sep 1^st, 2020 at 8:07pm by Oldman1950 »

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JS47 Frequent Elocutionist Offline Posts: 1265 Location: Arizona Joined: Oct 12^th, 2012	Re: Need Help with tin weight Reply #1 - Sep 1^st, 2020 at 10:55pm	Print Post
	I come up with 2.24 oz. but I'm mathematically challenged JS


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JLouis Frequent Elocutionist Offline Posts: 10625 Joined: Apr 8^th, 2009	Re: Need Help with tin weight Reply #2 - Sep 2^nd, 2020 at 11:42am	Print Post
	Basic Rules for Hardening Lead- For every 1% additional tin, Brinell hardness increases 0.3. For every 1% additional antimony, Brinell hardness increases 0.9. For a simple equation, Brinell = 8.60 (Antimonial Lead) + ( 0.29 * Tin ) + ( 0.92 * Antimony )

	" It Is Better To Now Have Been A Has Been Than A Never Was Or A Wanna Be "
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wesg Senior Forum Member Offline Posts: 275 Joined: Sep 13^th, 2004	Re: Need Help with tin weight Reply #3 - Sep 3^rd, 2020 at 1:13am	Print Post
	14×16÷26×25÷20-14×16÷26=2.154 [ oz Pb now ] [oz Sn now] [add Sn] [ oz Sn you need ] Probably a simpler way, but I'm algebraically challenged. At least it works on my Samsung phone calculator.


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Oldman1950 Full Member Offline Posts: 238 Location: Virginia Joined: Feb 8^th, 2014	Re: Need Help with tin weight Reply #4 - Sep 3^rd, 2020 at 6:09pm	Print Post
	Thanks That is about the number I got but wasn't sure I didn't drop the one of forgot to carry the 9. LOL Thanks again A. J. Palik


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yamoon Oldtimer Offline NRA Life, ASSRA , GGCA, MCA Posts: 880 Location: Junction City Kansas Joined: Feb 11^th, 2012	Re: Need Help with tin weight Reply #5 - Sep 3^rd, 2020 at 11:21pm	Print Post
	if I added 1 part tin by weight to 25 parts lead by weight, I have 26 parts. Is this 25 to 1 mixture? Mike


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oneatatime Frequent Elocutionist Offline Posts: 3865 Location: Rocky Mountains Joined: Oct 30^th, 2011	Re: Need Help with tin weight Reply #6 - Sep 4^th, 2020 at 12:29am	Print Post
	Yes.


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JLouis Frequent Elocutionist Offline Posts: 10625 Joined: Apr 8^th, 2009	Re: Need Help with tin weight Reply #7 - Sep 4^th, 2020 at 1:56pm	Print Post
	I am not so sure if that is actually correct it should end up at 25 and not 26 but I could also be wrong. Either way I highly doubt if it would make any difference if always doing it the same way. I believe it is based on Proportioning and not by weight.

	" It Is Better To Now Have Been A Has Been Than A Never Was Or A Wanna Be "
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oneatatime Frequent Elocutionist Offline Posts: 3865 Location: Rocky Mountains Joined: Oct 30^th, 2011	Re: Need Help with tin weight Reply #8 - Sep 4^th, 2020 at 3:55pm	Print Post
	"1 to 25" is a ratio not a proportion. It could be expressed as 1:25 or one pound of tin to every 25 pounds of lead. A proportion (or fraction if you will) would be 1/25 of the 25 pounds is tin and the rest is lead.


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GrumpyBear Full Member Offline Posts: 139 Location: Western,Pa. Joined: Sep 30^th, 2017	Re: Need Help with tin weight Reply #9 - Sep 4^th, 2020 at 4:17pm	Print Post
	I've always understood it as 20:1 is 1 pound of tin to 19 pounds of lead so that you end up with 20 lbs. of alloy ?

	Μολὼν λαβέ Don't pick a fight with an old man. If he is too old to fight, he'll just kill you. Shash-yazhi -bear-cub Brian
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oneatatime Frequent Elocutionist Offline Posts: 3865 Location: Rocky Mountains Joined: Oct 30^th, 2011	Re: Need Help with tin weight Reply #10 - Sep 4^th, 2020 at 4:47pm	Print Post
	The expression for that 20 pounds would be 1:19 or 1 pound of tin to 19 pounds of lead, or 1/20 of the 20 pounds of alloy is tin.


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JLouis Frequent Elocutionist Offline Posts: 10625 Joined: Apr 8^th, 2009	Re: Need Help with tin weight Reply #11 - Sep 4^th, 2020 at 5:34pm	Print Post
	From RotoMetals it is 5% Tin & 95% Lead to equal 1-20

	" It Is Better To Now Have Been A Has Been Than A Never Was Or A Wanna Be "
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GrumpyBear Full Member Offline Posts: 139 Location: Western,Pa. Joined: Sep 30^th, 2017	Re: Need Help with tin weight Reply #12 - Sep 4^th, 2020 at 5:43pm	Print Post
	JLouis wrote on Sep 4^th, 2020 at 5:34pm: From RotoMetals it is 5% Tin & 95% Lead to equal 1-20 So 5% of 20 would equal 1 (part tin) And 95% of 20 would equal 19 (parts lead) Correct?

	Μολὼν λαβέ Don't pick a fight with an old man. If he is too old to fight, he'll just kill you. Shash-yazhi -bear-cub Brian
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oneatatime Frequent Elocutionist Offline Posts: 3865 Location: Rocky Mountains Joined: Oct 30^th, 2011	Re: Need Help with tin weight Reply #13 - Sep 4^th, 2020 at 6:32pm	Print Post
	1-20 doesn't mean anything. Tin in this case is 1/20 (5%) of the total. 1/20 means something and that something is 5% of the total. That mixture is actually 1:19, 1 to 19. It should not be called 1 to 20, that is mathematically incorrect. 1 to 20 (1:20, 1 pound of tin to 20 pounds of lead) would be 4.76% tin. If you want to pay for more tin and you find computing 5% of the weight of your lead and adding that much tin, go for it.


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JLouis Frequent Elocutionist Offline Posts: 10625 Joined: Apr 8^th, 2009	Re: Need Help with tin weight Reply #14 - Sep 4^th, 2020 at 6:59pm	Print Post
	GrumpyBear according to the folks who make it and sell it as such and that being RotoMetals I am in no position to question it.

	" It Is Better To Now Have Been A Has Been Than A Never Was Or A Wanna Be "
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