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Oldman1950
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Need Help with tin weight
Sep 1st, 2020 at 5:53pm
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I have 14 lbs. of 1:25 and wish to add tin to make it 1:20 How much tin do I add?
Anyone good with the numbers??

Thanks

A. J. Palik
« Last Edit: Sep 1st, 2020 at 8:07pm by Oldman1950 »  
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JS47
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Re: Need Help with tin weight
Reply #1 - Sep 1st, 2020 at 10:55pm
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I come up with 2.24 oz. but I'm mathematically challenged

JS
  
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JLouis
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Re: Need Help with tin weight
Reply #2 - Sep 2nd, 2020 at 11:42am
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Basic Rules for Hardening Lead- 
For every 1% additional tin, Brinell hardness increases 0.3.
For every 1% additional antimony, Brinell hardness increases 0.9.
For a simple equation,
Brinell = 8.60 (Antimonial Lead) + ( 0.29 * Tin ) + ( 0.92 * Antimony )
  

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wesg
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Re: Need Help with tin weight
Reply #3 - Sep 3rd, 2020 at 1:13am
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14×16÷26×25÷20-14×16÷26=2.154
[   oz Pb now  ]      [oz Sn now]  [add Sn]
[  oz Sn you need ]

Probably a simpler way, but I'm algebraically challenged. At least it works on my Samsung phone calculator.
  
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Oldman1950
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Re: Need Help with tin weight
Reply #4 - Sep 3rd, 2020 at 6:09pm
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Thanks
That is about the number I got but wasn't sure I didn't drop the one of forgot to carry the 9. LOL

Thanks again

A. J. Palik
  
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yamoon
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Re: Need Help with tin weight
Reply #5 - Sep 3rd, 2020 at 11:21pm
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if I added 1 part tin by weight to 25 parts lead by weight, I have 26 parts. Is this 25 to 1 mixture?
Mike
  
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oneatatime
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Re: Need Help with tin weight
Reply #6 - Sep 4th, 2020 at 12:29am
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Yes.
  
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JLouis
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Re: Need Help with tin weight
Reply #7 - Sep 4th, 2020 at 1:56pm
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I am not so sure if that is actually correct it should end up at 25 and not 26 but I could also be wrong. Either way I highly doubt if it would make any difference if always doing it the same way. I believe it is based on Proportioning and not by weight.
  

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oneatatime
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Re: Need Help with tin weight
Reply #8 - Sep 4th, 2020 at 3:55pm
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"1 to 25" is a ratio not a proportion. It could be expressed as 1:25 or one pound of tin to every 25 pounds of lead. A proportion (or fraction if you will) would be 1/25 of the 25 pounds is tin and the rest is lead.
  
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GrumpyBear
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Re: Need Help with tin weight
Reply #9 - Sep 4th, 2020 at 4:17pm
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I've always understood it as 20:1 is 1 pound of tin to 19 pounds of lead so that you end up with 20 lbs. of alloy ?
  

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oneatatime
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Re: Need Help with tin weight
Reply #10 - Sep 4th, 2020 at 4:47pm
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The expression for that 20 pounds would be 1:19 or 1 pound of tin to 19 pounds of lead, or 1/20 of the 20 pounds of alloy is tin.
  
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JLouis
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Re: Need Help with tin weight
Reply #11 - Sep 4th, 2020 at 5:34pm
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From RotoMetals it is 5% Tin & 95% Lead to equal 1-20
  

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GrumpyBear
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Re: Need Help with tin weight
Reply #12 - Sep 4th, 2020 at 5:43pm
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JLouis wrote on Sep 4th, 2020 at 5:34pm:
From RotoMetals it is 5% Tin & 95% Lead to equal 1-20


So 5% of 20 would equal 1 (part tin)

And 95% of 20 would equal 19 (parts lead)

Correct?
  

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oneatatime
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Re: Need Help with tin weight
Reply #13 - Sep 4th, 2020 at 6:32pm
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1-20 doesn't mean anything. Tin in this case is 1/20 (5%) of the total. 1/20 means something and that something is 5% of the total. That mixture is actually 1:19, 1 to 19. It should not be called 1 to 20, that is mathematically incorrect. 1 to 20 (1:20, 1 pound of tin to 20 pounds of lead) would be  4.76% tin. If you want to pay for more tin and you find computing 5% of the weight of your lead and adding that much tin, go for it.
  
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JLouis
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Re: Need Help with tin weight
Reply #14 - Sep 4th, 2020 at 6:59pm
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GrumpyBear according to the folks who make it and sell it as such and that being RotoMetals I am in no position to question it.
  

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