Consider these numbers from
(You need to Login or Register to view media files and links) online ballistics program.
Muzzle velocity - 1500 ft/sec, time of flight (1000 yds) 2.881 sec. Wind drift (10 mph at 90 degrees) 155.2 inches.
Muzzle velocity - 1000 ft/sec, time of flight (1000 yds) 3.623 sec. Wind drift (10 mph at 90 degrees) 109.6 inches.
Less drift at 1000 ft/sec than at 1500 ft/sec.
Basically, wind drift isn't a function of how long the bullet is in flight but rather how long it takes the bullet to get to the target minus how long it would take to get to the target in a vacuum. (no air resistance)
The mathematical formula is: D = ws(T-t).
Where D is the drift of the bullet.
ws is the component of the wind speed perpendicular to the bullet path.
T is the time it actually takes the bullet to reach the target.
t the time it would take the bullet to reach the target in a vacuum.
The expression "T - t" is sometimes referred to as the "lag time".
To get the value of "t" just divide the range by the muzzle velocity.
At 1500 ft/sec t = 2.000 (3000/1500). At 1000 ft/sec t = 3.0 (3000/1000)
Therefore at 1500 ft/sec mv the lag time is .881 sec. (2.881 - 2.000). At 1000 ft/sec mv the lag time is .623 sec (3.623 - 3.000)
10 m/hr = 176 in/sec.
At 1000 ft/sec D = 176 x .623 = 109.6 in.
At 1500 ft/sec D = 176 X .881 = 155.0 in.
It's counter intuitive but real. Bullets below the speed of sound have less "time lag" as they travel downrange so have less wind drift.
Sorry about the math, I can't help it, I'm a retired math and physics teacher.
B'duckie